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			103 lines
		
	
	
		
			3.2 KiB
		
	
	
	
		
			JavaScript
		
	
	
	
	
	
			
		
		
	
	
			103 lines
		
	
	
		
			3.2 KiB
		
	
	
	
		
			JavaScript
		
	
	
	
	
	
//
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// This takes a string and parsed out first and last names
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//   accepts comma separated lists e.g. "Jon Smith, Jane Smith" or "Smith, Jon, Smith, Jane"
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//   can be separated by "&" e.g. "Jon Smith & Jane Smith" or "Smith, Jon & Smith, Jane"
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//
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const parseFullName = require('./parseFullName')
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function parseName(name) {
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  var parts = parseFullName(name)
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  var firstName = parts.first
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  if (firstName && parts.middle) firstName += ' ' + parts.middle
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  return {
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    first_name: firstName,
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    last_name: parts.last
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  }
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}
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// Check if this name segment is of the format "Last, First" or "First Last"
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// return true is "Last, First"
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function checkIsALastName(name) {
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  if (!name.includes(' ')) return true // No spaces must be a Last name
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  var parsed = parseFullName(name)
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  if (!parsed.first) return true // had spaces but not a first name i.e. "von Mises", must be last name only
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  return false
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}
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// Handle name already in First Last format and return Last, First
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module.exports.nameToLastFirst = (firstLast) => {
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  var nameObj = parseName(firstLast)
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  if (!nameObj.last_name) return nameObj.first_name
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  else if (!nameObj.first_name) return nameObj.last_name
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  return `${nameObj.last_name}, ${nameObj.first_name}`
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}
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// Handle any name string
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module.exports.parse = (nameString) => {
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  if (!nameString) return null
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  var splitNames = []
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  // Example &LF: Friedman, Milton & Friedman, Rose
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  if (nameString.includes('&')) {
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    nameString.split('&').forEach((asa) => (splitNames = splitNames.concat(asa.split(','))))
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  } else if (nameString.includes(' and ')) {
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    nameString.split(' and ').forEach((asa) => (splitNames = splitNames.concat(asa.split(','))))
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  } else if (nameString.includes(';')) {
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    nameString.split(';').forEach((asa) => (splitNames = splitNames.concat(asa.split(','))))
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  } else {
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    splitNames = nameString.split(',')
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  }
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  if (splitNames.length) splitNames = splitNames.map((a) => a.trim())
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  // If names are in Chinese,Japanese and Korean languages, return as is.
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  if (/[\u4e00-\u9fff\u3040-\u30ff\u31f0-\u31ff]/.test(splitNames[0])) {
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    return {
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      names: splitNames
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    }
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  }
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  var names = []
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  // 1 name FIRST LAST
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  if (splitNames.length === 1) {
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    names.push(parseName(nameString))
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  } else {
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    var firstChunkIsALastName = checkIsALastName(splitNames[0])
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    var isEvenNum = splitNames.length % 2 === 0
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    if (!isEvenNum && firstChunkIsALastName) {
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      // console.error('Multi-name LAST,FIRST entry has a straggler (could be roman numerals or a suffix), ignore it')
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      splitNames = splitNames.slice(0, splitNames.length - 1)
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    }
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    if (firstChunkIsALastName) {
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      var num = splitNames.length / 2
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      for (let i = 0; i < num; i++) {
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        var last = splitNames.shift()
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        var first = splitNames.shift()
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        names.push({
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          first_name: first,
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          last_name: last
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        })
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      }
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    } else {
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      splitNames.forEach((segment) => {
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        names.push(parseName(segment))
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      })
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    }
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  }
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  // Filter out names that have no first and last
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  names = names.filter((n) => n.first_name || n.last_name)
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  // Set name strings and remove duplicates
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  const namesArray = [...new Set(names.map((a) => (a.first_name ? `${a.first_name} ${a.last_name}` : a.last_name)))]
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  return {
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    names: namesArray // Array of first last
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  }
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}
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