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Get rid of the check for break iterator since the spell code wont exist for long in master without a matching binary release

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This commit is contained in:
Kovid Goyal 2014-04-17 10:12:02 +05:30
parent 7088ae51db
commit 17ac015c64
2 changed files with 7 additions and 14 deletions
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9
src/calibre/ebooks/oeb/polish/spell.py
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@ -9,7 +9,7 @@ __copyright__ = '2014, Kovid Goyal <kovid at kovidgoyal.net>'
import sys
from collections import defaultdict
from calibre.spell.break_iterator import has_break_iterator, split_into_words
from calibre.spell.break_iterator import split_into_words
from calibre.spell.dictionary import parse_lang_code
from calibre.ebooks.oeb.base import barename
from calibre.ebooks.oeb.polish.container import OPF_NAMESPACES, get_container
@ -56,17 +56,12 @@ def filter_words(word):
return False
return True
if has_break_iterator:
def get_words(text, lang):
def get_words(text, lang):
try:
ans = split_into_words(unicode(text), lang)
except (TypeError, ValueError):
return ()
return filter(filter_words, ans)
else:
def get_words(text, lang):
p = patterns()
return filter(filter_words, p.split_pat.split(text))
def add_words(text, sourceline, words, file_name, locale):
candidates = get_words(text, locale.langcode)

2
src/calibre/spell/break_iterator.py
View File

@ -14,8 +14,6 @@ from calibre.utils.localization import lang_as_iso639_1
_iterators = {}
_lock = Lock()
has_break_iterator = hasattr(_icu, 'BreakIterator')
def split_into_words(text, lang='en'):
with _lock:
it = _iterators.get(lang, None)