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Do not output baselib code in the REPL

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Kovid Goyal 2015-06-21 09:50:08 +05:30
parent fd5c130731
commit 1d34f92c12
1 changed files with 6 additions and 1 deletions
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7
src/calibre/utils/rapydscript.py
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@ -125,6 +125,7 @@ def compiler():
from duktape import Context
c = tls.compiler = Context(base_dirs=(P('rapydscript', allow_user_override=False),))
c.eval(P(COMPILER_PATH, data=True, allow_user_override=False).decode('utf-8'), fname='rapydscript-compiler.js')
c.g.current_output_options = {}
return c
class PYJError(Exception):
@ -192,6 +193,10 @@ class Repl(object):
except ImportError:
pass
self.output = ANSIStream(sys.stdout)
c = compiler()
baselib = dict(dict(c.g.rs_baselib_pyj)['beautifed'])
baselib = '\n\n'.join(baselib.itervalues())
self.ctx.eval(baselib)
def resetbuffer(self):
self.lines = []
@ -260,7 +265,7 @@ class Repl(object):
def runsource(self, source):
try:
js = compile_pyj(source, filename='', private_scope=False, libdir=self.libdir)
js = compile_pyj(source, filename='', private_scope=False, libdir=self.libdir, omit_baselib=True)
except PYJError as e:
for data in e.errors:
msg = data.get('message') or ''