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Only detect the template type keyword on the first line.

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Remove an extra space from the default formatter exception message.
This commit is contained in:
Charles Haley 2022-10-10 21:06:09 +01:00
parent f1f8c32975
commit 294a28433c
2 changed files with 9 additions and 2 deletions
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9
src/calibre/gui2/dialogs/template_dialog.py
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@ -216,7 +216,14 @@ class TemplateHighlighter(QSyntaxHighlighter):
pp = self.find_paren(bn, i)
if pp and pp.highlight:
self.setFormat(i, length, self.Formats[format_])
elif format_ == 'keyword':
if bn > 0 and i == 0:
if text[i:i+length] == ('python:' if self.for_python else 'program:'):
continue
print('bn', bn, format_, text[i:i+length])
self.setFormat(i, length, self.Formats[format_])
else:
print('bn', bn, format_, text[i:i+length])
self.setFormat(i, length, self.Formats[format_])
self.setCurrentBlockState(NORMAL)
@ -796,7 +803,7 @@ class TemplateDialog(QDialog, Ui_TemplateDialog):
w = tv.cellWidget(r, 0)
w.setText(mi.title)
w.setCursorPosition(0)
v = SafeFormat().safe_format(txt, mi, _('EXCEPTION: '),
v = SafeFormat().safe_format(txt, mi, _('EXCEPTION:'),
mi, global_vars=self.global_vars,
template_functions=self.all_functions,
break_reporter=self.break_reporter if r == break_on_mi else None)

2
src/calibre/utils/formatter.py
View File

@ -1591,7 +1591,7 @@ class TemplateFormatter(string.Formatter):
raise(ValueError(
_('Syntax error on line {0} column {1}: text {2}').format(e.lineno, e.offset, e.text)))
except KeyError:
raise(ValueError(_("Error: the {0} function is not defined in the template").format('evaluate')))
raise(ValueError(_("The {0} function is not defined in the template").format('evaluate')))
# ################# Override parent classes methods #####################