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Ensure correct base directory is used when compiling with CALIBRE_DEVELOP_FROM

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Kovid Goyal 2017-05-27 22:37:56 +05:30
parent dee602246b
commit 3a270f77c5
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1 changed files with 7 additions and 3 deletions
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10
src/calibre/utils/rapydscript.py
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@ -194,9 +194,13 @@ def create_manifest(html):
h.hexdigest(), manifest).encode('utf-8')
def compile_srv():
def base_dir():
d = os.path.dirname
base = d(d(d(d(os.path.abspath(__file__)))))
return d(d(d(d(os.path.abspath(__file__)))))
def compile_srv():
base = base_dir()
iconf = os.path.join(base, 'imgsrc', 'srv', 'generate.py')
g = {'__file__': iconf}
execfile(iconf, g)
@ -213,7 +217,7 @@ def compile_srv():
if e.errno != errno.ENOENT:
raise
mathjax_version = '0'
base = P('content-server', allow_user_override=False)
base = os.path.join(base, 'resources', 'content-server')
fname = os.path.join(rapydscript_dir, 'srv.pyj')
with lopen(fname, 'rb') as f:
js = compile_fast(f.read(), fname).replace(