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Workaround for dictionaries that use incorrect relative paths in their .xcu files. Fixes #1477561 [Unable to import italian dictionary](https://bugs.launchpad.net/calibre/+bug/1477561)

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This commit is contained in:
Kovid Goyal 2015-07-23 21:36:34 +05:30
parent 8f75f2d5ad
commit 5edd84e213
1 changed files with 14 additions and 1 deletions
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15
src/calibre/spell/import_from.py
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@ -104,6 +104,19 @@ def import_from_oxt(source_path, name, dest_dir=None, prefix='dic-'):
os.makedirs(dest_dir) os.makedirs(dest_dir)
num = 0 num = 0
with ZipFile(source_path) as zf: with ZipFile(source_path) as zf:
def read_file(key):
try:
return zf.open(key).read()
except KeyError:
# Some dictionaries apparently put the xcu in a sub-directory
# and incorrectly make paths relative to that directory instead
# of the root, for example:
# http://extensions.libreoffice.org/extension-center/italian-dictionary-thesaurus-hyphenation-patterns/releases/4.1/dict-it.oxt
while key.startswith('../'):
key = key[3:]
return zf.open(key.lstrip('/')).read()
root = etree.fromstring(zf.open('META-INF/manifest.xml').read()) root = etree.fromstring(zf.open('META-INF/manifest.xml').read())
xcu = XPath('//manifest:file-entry[@manifest:media-type="application/vnd.sun.star.configuration-data"]')(root)[0].get( xcu = XPath('//manifest:file-entry[@manifest:media-type="application/vnd.sun.star.configuration-data"]')(root)[0].get(
'{%s}full-path' % NS_MAP['manifest']) '{%s}full-path' % NS_MAP['manifest'])
@ -116,7 +129,7 @@ def import_from_oxt(source_path, name, dest_dir=None, prefix='dic-'):
metadata = [name] + list(locales) metadata = [name] + list(locales)
with open(os.path.join(d, 'locales'), 'wb') as f: with open(os.path.join(d, 'locales'), 'wb') as f:
f.write(('\n'.join(metadata)).encode('utf-8')) f.write(('\n'.join(metadata)).encode('utf-8'))
dd, ad = convert_to_utf8(zf.open(dic).read(), zf.open(aff).read()) dd, ad = convert_to_utf8(read_file(dic), read_file(aff))
with open(os.path.join(d, '%s.dic' % locales[0]), 'wb') as f: with open(os.path.join(d, '%s.dic' % locales[0]), 'wb') as f:
f.write(dd) f.write(dd)
with open(os.path.join(d, '%s.aff' % locales[0]), 'wb') as f: with open(os.path.join(d, '%s.aff' % locales[0]), 'wb') as f: