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Remove problematic string from translations

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Kovid Goyal 2024-12-05 20:49:32 +05:30
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commit 6b98fac7c3
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src/calibre/utils/formatter_functions.py
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@ -1844,11 +1844,12 @@ You can use expressions to generate a list. For example, assume you want items
for ``authors`` and ``#genre``, but with the genre changed to the word "Genre: " for ``authors`` and ``#genre``, but with the genre changed to the word "Genre: "
followed by the first letter of the genre, i.e. the genre "Fiction" becomes followed by the first letter of the genre, i.e. the genre "Fiction" becomes
"Genre: F". The following will do that: "Genre: F". The following will do that:
{}''').format('''\
[CODE] [CODE]
program: program:
list_join('#@#', $authors, '&', list_re($#genre, ',', '^(.).*$', 'Genre: \1'), ',') list_join('#@#', $authors, '&', list_re($#genre, ',', '^(.).*$', 'Genre: \1'), ',')
[/CODE] [/CODE]
''') ''') # not translated as \1 gets mistranslated as a control char in transifex for some reason
def evaluate(self, formatter, kwargs, mi, locals, with_separator, *args): def evaluate(self, formatter, kwargs, mi, locals, with_separator, *args):
if len(args) % 2 != 0: if len(args) % 2 != 0: