TXT Input: Detect and retain soft scene breaks.

This commit is contained in:
John Schember 2011-01-26 20:15:44 -05:00
parent 6026c86ecc
commit 8bd3c8d53e

View File

@ -31,7 +31,7 @@ def clean_txt(txt):
txt = re.sub('^\s+(?=.)', '', txt)
txt = re.sub('(?<=.)\s+$', '', txt)
# Remove excessive line breaks.
txt = re.sub('\n{3,}', '\n\n', txt)
txt = re.sub('\n{5,}', '\n\n\n\n', txt)
#remove ASCII invalid chars : 0 to 8 and 11-14 to 24
txt = clean_ascii_chars(txt)
@ -59,10 +59,16 @@ def convert_basic(txt, title='', epub_split_size_kb=0):
txt = split_txt(txt, epub_split_size_kb)
lines = []
blank_count = 0
# Split into paragraphs based on having a blank line between text.
for line in txt.split('\n\n'):
for line in txt.split('\n'):
if line.strip():
blank_count = 0
lines.append(u'<p>%s</p>' % prepare_string_for_xml(line.replace('\n', ' ')))
else:
blank_count += 1
if blank_count == 2:
lines.append(u'<p>&nbsp;</p>')
return HTML_TEMPLATE % (title, u'\n'.join(lines))
@ -85,7 +91,8 @@ def normalize_line_endings(txt):
return txt
def separate_paragraphs_single_line(txt):
txt = re.sub(u'(?<=.)\n(?=.)', '\n\n', txt)
#txt = re.sub(u'(?<=.)\n(?=.)', '\n\n', txt)
txt = txt.replace('\n', '\n\n')
return txt
def separate_paragraphs_print_formatted(txt):