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Make google id_from_url() more robust

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Kovid Goyal 2022-04-15 09:00:06 +05:30
parent 37c607b3f6
commit 8f9a62f2fc
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1 changed files with 7 additions and 7 deletions
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14
src/calibre/ebooks/metadata/sources/google.py
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@ -201,13 +201,13 @@ class GoogleBooks(Source):
# }}}
def id_from_url(self, url): # {{{
url_pattern = r'(?:http|https)://books\.google\.com/books\?id=(?P<id_>.+)'
url_pattern = re.compile(url_pattern)
id_ = url_pattern.search(url).group('id_')
if id_:
return ('google', id_)
else:
return None
from polyglot.urllib import urlparse, parse_qs
purl = urlparse(url)
if purl.netloc == 'books.google.com':
q = parse_qs(purl.query)
gid = q.get('id')
if gid:
return 'google', gid[0]
# }}}
def create_query(self, title=None, authors=None, identifiers={}, capitalize_isbn=False): # {{{