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DOCX Input: Handle docx files with index fields that have their field names incorrectly lower cased. Fixes #1318670 [Conversion from DOCX, probably indexitem related](https://bugs.launchpad.net/calibre/+bug/1318670)
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@ -126,10 +126,13 @@ class Fields(object):
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field_types = ('hyperlink', 'xe', 'index', 'ref', 'noteref')
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parsers = {x.upper():getattr(self, 'parse_'+x) for x in field_types}
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parsers.update({x:getattr(self, 'parse_'+x) for x in field_types})
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field_parsers = {f.upper():globals()['parse_%s' % f] for f in field_types}
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field_parsers.update({f:globals()['parse_%s' % f] for f in field_types})
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for f in field_types:
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setattr(self, '%s_fields' % f, [])
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unknown_fields = {'TOC', 'toc', 'PAGEREF', 'pageref'} # The TOC and PAGEREF fields are handled separately
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for field in self.fields:
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field.finalize()
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@ -137,6 +140,9 @@ class Fields(object):
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func = parsers.get(field.name, None)
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if func is not None:
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func(field, field_parsers[field.name], log)
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elif field.name not in unknown_fields:
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log.warn('Encountered unknown field: %s, ignoring it.' % field.name)
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unknown_fields.add(field.name)
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def get_runs(self, field):
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all_runs = []
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@ -200,6 +206,8 @@ class Fields(object):
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return
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idx = parse_func(field.instructions, log)
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hyperlinks, blocks = process_index(field, idx, self.xe_fields, log)
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if not blocks:
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return
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for anchor, run in hyperlinks:
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self.hyperlink_fields.append(({'anchor':anchor}, [run]))
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@ -91,7 +91,7 @@ def process_index(field, index, xe_fields, log):
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xe_fields = get_applicable_xe_fields(index, xe_fields)
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if not xe_fields:
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return
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return [], []
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if heading_text is not None:
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groups = partition_by_first_letter(xe_fields, key=itemgetter('text'))
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items = []
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@ -138,7 +138,7 @@ def split_up_block(block, a, text, parts, ldict):
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"""
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The merge algorithm is a little tricky.
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We start with a list of elementary blocks. Each is an HtmlElement, a p node
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with a list of child nodes. The last child is a link, and the earlier ones are
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with a list of child nodes. The last child is a link, and the earlier ones are
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just text.
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The list is in reverse order from what we want in the index.
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There is a dictionary ldict which records the level of each child node.
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@ -159,7 +159,7 @@ If there are no more levels in n, then add the link from nk to the links for pk.
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This might be the first link for pk, or we might get a list of references.
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Otherwise nk+1 is the next level in n. Look for a matching entry in p. It must have
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the same text, it must follow pk, it must come before we find any other p entries at
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the same text, it must follow pk, it must come before we find any other p entries at
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the same level as pk, and it must have the same level as nk+1.
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If we find such a matching entry, go back to the start with (p ... pk+1) and (n ... nk+1).
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@ -208,7 +208,7 @@ def merge_blocks(prev_block, next_block, pind, nind, next_path, ldict):
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if prevent > 0:
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merge_blocks(prev_block, next_block, prevent, nind, next_path, ldict)
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return
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# Want to insert elements into previous block
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while nind < len(next_block):
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# insert takes it out of old
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