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pep8
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00038f3207
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@ -11,7 +11,7 @@ DOC = '''
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Trailing Byte Sequences contain information about which index entries touch a
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Trailing Byte Sequences contain information about which index entries touch a
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particular text record. Every text records has a set of trailing byte
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particular text record. Every text records has a set of trailing byte
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sequences. In order to figure out the sequence for a given text record, you
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sequences. In order to figure out the sequence for a given text record, you
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have to first calculate all the indices that start, end, span and anre
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have to first calculate all the indices that start, end, span and are
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contained within that text record. Then arrange the indices into 'strands',
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contained within that text record. Then arrange the indices into 'strands',
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where each strand is a hierarchical progression from the top level index down.
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where each strand is a hierarchical progression from the top level index down.
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For the exact algorithm, see separate_strands(). The strands are then encoded
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For the exact algorithm, see separate_strands(). The strands are then encoded
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@ -60,7 +60,7 @@ def populate_strand(parent, entries):
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children = [c for c in entries if c.parent == entry.index]
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children = [c for c in entries if c.parent == entry.index]
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if children:
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if children:
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siblings += populate_strand(entry, entries)
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siblings += populate_strand(entry, entries)
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break # Cannot add more siblings, as we have added children
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break # Cannot add more siblings, as we have added children
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else:
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else:
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siblings.append(entry)
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siblings.append(entry)
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ans += siblings
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ans += siblings
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@ -176,7 +176,7 @@ def sequences_to_bytes(sequences):
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flag_size = 3
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flag_size = 3
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for val, extra in sequences:
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for val, extra in sequences:
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ans.append(encode_tbs(val, extra, flag_size))
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ans.append(encode_tbs(val, extra, flag_size))
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flag_size = 4 # only the first sequence has flag size 3 as all
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flag_size = 4 # only the first sequence has flag size 3 as all
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# subsequent sequences could need the 0b1000 flag
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# subsequent sequences could need the 0b1000 flag
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return b''.join(ans)
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return b''.join(ans)
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