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Use the full style key to avoid repeat embed instead of just the family name

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This commit is contained in:
Kovid Goyal 2016-11-15 17:32:46 +05:30
parent 77fd17c763
commit c4b9994629
1 changed files with 9 additions and 3 deletions
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12
src/calibre/ebooks/oeb/transforms/embed_fonts.py
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@ -17,6 +17,7 @@ from calibre.ebooks.oeb.base import XPath, CSS_MIME, XHTML
from calibre.ebooks.oeb.transforms.subset import get_font_properties, find_font_face_rules, elem_style
from calibre.utils.filenames import ascii_filename
from calibre.utils.fonts.scanner import font_scanner, NoFonts
from calibre.ebooks.oeb.polish.embed import font_key
def font_families_from_style(style):
@ -24,9 +25,14 @@ def font_families_from_style(style):
'serif', 'sansserif', 'sans-serif', 'fantasy', 'cursive', 'monospace'}]
def style_key(style):
style = style.copy()
style['font-family'] = font_families_from_style(style)[0]
return font_key(style)
def font_already_embedded(style, newly_embedded_fonts):
ff = font_families_from_style(style)
return not ff or ff[0] in newly_embedded_fonts
return style_key(style) in newly_embedded_fonts
def used_font(style, embedded_fonts):
@ -188,6 +194,7 @@ class EmbedFonts(object):
# Try to find the font in the system
added = self.embed_font(style)
if added is not None:
self.newly_embedded_fonts.add(style_key(style))
ff_rules.append(added)
self.embedded_fonts.append(added)
else:
@ -232,7 +239,6 @@ class EmbedFonts(object):
f['font-family'], f['font-weight'], f['font-style'], f['font-stretch'], href)
sheet = self.parser.parseString(css, validate=False)
page_sheet.data.insertRule(sheet.cssRules[0], len(page_sheet.data.cssRules))
self.newly_embedded_fonts.add(ff)
return find_font_face_rules(sheet, self.oeb)[0]
for f in fonts: