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Change tag browser to handle multi-character "characters" that some languages use when doing first letter categorization.

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This commit is contained in:
Charles Haley 2012-07-05 17:44:36 +02:00
parent c9e37072a9
commit d5e7f83da4
1 changed files with 16 additions and 11 deletions
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27
src/calibre/gui2/tag_browser/model.py
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@ -17,7 +17,7 @@ from PyQt4.Qt import (QAbstractItemModel, QIcon, QVariant, QFont, Qt,
from calibre.gui2 import NONE, gprefs, config, error_dialog
from calibre.library.database2 import Tag
from calibre.utils.config import tweaks
from calibre.utils.icu import sort_key, lower, strcmp, span_contractions
from calibre.utils.icu import sort_key, lower, strcmp, contractions
from calibre.library.field_metadata import TagsIcons, category_icon_map
from calibre.gui2.dialogs.confirm_delete import confirm
from calibre.utils.formatter import EvalFormatter
@ -259,6 +259,16 @@ class TagsModel(QAbstractItemModel): # {{{
self.hidden_categories.add(cat)
db.prefs.set('tag_browser_hidden_categories', list(self.hidden_categories))
conts = contractions()
if len(conts) == 0:
self.do_contraction = False
else:
self.do_contraction = True
nconts = set()
for s in conts:
nconts.add(icu_upper(s))
self.contraction_set = frozenset(nconts)
self.db = db
self._run_rebuild()
self.endResetModel()
@ -379,10 +389,6 @@ class TagsModel(QAbstractItemModel): # {{{
else:
collapse_model = 'partition'
collapse_template = tweaks['categories_collapsed_popularity_template']
if True or get_lang() in self.langs_no_span_contractions:
use_span_contractions = False
else:
use_span_contractions = True
def get_name_components(name):
components = [t.strip() for t in name.split('.') if t.strip()]
@ -423,15 +429,14 @@ class TagsModel(QAbstractItemModel): # {{{
if not tag.sort:
c = ' '
else:
if not use_span_contractions:
if not self.do_contraction:
c = icu_upper(tag.sort)[0]
else:
v = icu_upper(tag.sort)
le = span_contractions(v)
if le > 0:
c = v[:le]
else:
c = v[0]
c = v[0]
for s in self.contraction_set:
if len(s) > len(c) and v.startswith(s):
c = s
if c not in chardict:
chardict[c] = [idx, idx]
else: